Answer:
a. the current in the other second wire is 820.78 Ampere
b. the two currents are in opposite directions
Explanation:
a. the current in the second wire is given by the expression for the force per unit lenght between two wires
[tex]\frac{F}{l} = \frac{U_{0}I_{1} I_{2} }{2\pi r}[/tex]
where [tex]U_{0} = 4\pi X10^{-7}[/tex]
substituting all these values into the expression for the force per unit length and then making [tex]I_{2}[/tex] the subject
Note: convert 2.3 cm to meters = 0.023 meters
[tex]5.00X10^{-5} =(4\pi X10^{-7} )(0.700)I_{2} / 2\pi (0.023)[/tex]
making [tex]I_{2}[/tex] subject
[tex]I_{2}=\frac{(5.00X10^{-5})(2\pi )(0.023)}{(4\pi X10^{-7})(0.700) }[/tex]
simplifying will give
[tex]I_{2} =8.22 A[/tex]
b. the force is attractive if the currents are in the same direction and repulsive if the force are in opposite directions
