A website offers a coupon to 50, percent of its visitors, selected at random, each day. Yasemin visits the website for 4 days. What is the probability that Yasemin will not be offered a coupon on at least one of the days she visits the website? Round your answer to the nearest hundredth.

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desislava2001 desislava2001 · Answer 1 · 2020-01-18T20:01:57+01:00

Answer:

0.94

Step-by-step explanation:

P(at least one day without coupon)

=1−P(all 4 with coupon)

=1−0.5

4

=1−0.0625

=0.9375

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MrRoyal MrRoyal · Answer 2 · 2021-12-09T12:27:02+01:00

Probabilities are used to determine the chances of events

The probability that he is not offered a coupon at least one day is 0.9375

The probability that a visitor is offered a coupon is given as:

[tex]p = 50\%[/tex]

The probability that he gets coupon all 4 days is:

[tex]P(4) = p^4[/tex]

This gives

[tex]P(4) = (50\%)^4[/tex]

[tex]P(4) = 0.0625[/tex]

Using the complement rule, the probability that he is not offered a coupon at least one day is:

[tex]P' = 1 - P(4)[/tex]

So, we have:

[tex]P' = 1 - 0.0625[/tex]

Subtract

[tex]P' = 0.9375[/tex]

Hence, the probability that he is not offered a coupon at least one day is 0.9375