Answer:
[tex]m = 4.26 kg[/tex]
Explanation:
As we know that heat required to remove from water to freeze it is given as
[tex]Q = mL[/tex]
so we have 1.4 kg water is required to freeze
so heat is given as
[tex]Q_1 = 1.4 \times 3.35 \times 10^5[/tex]
now same heat is removed from ethyl alcohol of mass "m"
the latent heat of fusion for ethyl alcohol is given as
[tex]L = 1.1 \times 10^5 J/kg[/tex]
so we have
[tex]Q_2 = m(1.1 \times 10^5)[/tex]
now we know
[tex]Q_1 = Q_2[/tex]
[tex]1.4 \times 3.35 \times 10^5 = m(1.1 \times 10^5)[/tex]
[tex]m = 4.26 kg[/tex]
