Answer:
P = 430 W
Explanation:
As we know that net rate of heat radiation into the room is given as
[tex]\frac{dQ}{dt} = \sigma A(T^4 - T_s^4)[/tex]
here we have
[tex]\sigma = 5.67 \times 10^{-8}[/tex]
[tex]A = 4\pi r^2[/tex]
[tex]A = 4\pi(0.10^2)[/tex]
[tex]A = 0.125 m^2[/tex]
now we have
[tex]P = (5.67 \times 10^{-8})(0.125)(510^4 - 293^4)[/tex]
[tex]P = 430 W[/tex]