Answer:
13.14×10^{-3} atm
Explanation:
[tex]2O_3(g)\rightarrow3O_2(g)[/tex]
therefore, rate is given as
= [tex]-\frac{1}{2}\frac{dO_3}{dt} = +\frac{1}{3} \frac{dO_2}{dt}[/tex]
=[tex]\frac{dO_2}{dt} = +\frac{3}{2} \frac{dO_3}=\frac{3}{2}\times8.76\times10^{-3}{dt}[/tex]
= 13.14×10^{-3} atm
