Answer:
1.88 g
Explanation:
Considering:-
[tex]\%\ of\ the\ citral=\frac{Volume_{citral}}{Volume_{Sample}}\times 100[/tex]
Given that:-
% Citral = 5.72 %
Volume of the citral = 0.120 mL
So,
[tex]5.72=\frac{0.120\ mL}{Volume_{Sample}}\times 100[/tex]
[tex]Volume_{Sample}=\frac{0.120\times 100}{5.72}\ mL[/tex]
Volume of the grass oil sample = 2.10 mL
Also, Density of the lemon grass oil = 0.893 g/mL
Mass = Density*Volume = 0.893 g/mL*2.10 mL = 1.88 g
1.88 g of lemon grass oil did you begin with if citral comprises 5.72% of the oil.
Answer:
1.84 g/mL
Explanation:
We know that
percentage of citral = [tex]\frac{Volume of citral}{Volume of sample }[/tex]
⇒[tex]\frac{5.72}{100} =\frac{0.120}{V_{sample}}[/tex]
solving for V_sample we get 2.09 mL
Now density of the lemon grass oil = 0.88g/mL at room temp.
then mass in gm= Volume×Density= 2.09×0.88 =1.84 gram.
