Answer:
V = 497.6 L
Explanation:
Given data:
Mass of C₃H₈ = 325 g
Volume of carbon dioxide produced at STP = ?
Solution:
Chemical equation;
C₃H₈ + 5O₂ → 3CO₂ +4 H₂O
Number of moles of C₃H₈ :
Number of moles = mass/ molar mass
Number of moles = 325 g/ 44.1 g/mol
Number of moles = 7.4 mol
Now we will compare the moles of carbon dioxide with C₃H₈ .
C₃H₈ : CO₂
1 : 3
7.4 : 3×7.4 = 22.2 mol
Volume of carbon dioxide at STP:
PV = nRT
V = nRT/P
V = 22.2 mol × 0.0821 atm. L/mol.k × 273 K / 1 atm
V = 497.6 L
