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Two people push on a boulder to try to move it. The mass of the boulder is 775 kg. One person pushes north with a force of 68 N. The other pushes west with a force of 43 N. Predict the magnitude of the acceleration (in m/s2) of the boulder. Assume that friction is negligible.

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The magnitude of the acceleration is 0.1038 m/s²

Explanation:

Net force is given by the square root of the sum of squares of the forces in y and x coordinates

Absolute Net Force will be;

[tex]Nf=\sqrt{(Fx)^2+(Fy)^2} \\\\\\Nf=\sqrt{(68)^2+(43)^2} \\\\\\Nf=80.45N[/tex]

However, Fnet can be calculated as the product of force and acceleration

Fnet=m*a

Fnet= 80.45 N

m= 775 kg

a=?

80.45=775*a

80.45/775= a

0.1038 m/s²=a

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To calculate force : https://brainly.com/question/8829131

Keywords : mass, force, magnitude, acceleration

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