Answer:
The zeros of the function are x = -1.35 and x = 1.85
Step-by-step explanation:
The given function is f(x) = x + 5 - 2x²
⇒ f(x) = - 2x² + x + 5
To find the zeroes of the function we are assuming f(x) = 0 and solve the equations.
Hence, - 2x² + x + 5 = 0
Applying Sridhar Acharya's formula
[tex]x = \frac{-1 + \sqrt{1^{2} - 4 (- 2)(5) } }{2(- 2)}[/tex] and [tex]x = \frac{-1 - \sqrt{1^{2} - 4 (- 2)(5) } }{2(- 2)}[/tex]
⇒ [tex]x = \frac{- 1 + 6.4}{-4}[/tex] and [tex]x = \frac{- 1 - 6.4}{-4}[/tex]
⇒ x = -1.35 and x = 1.85
Therefore, the zeros of the function are x = -1.35 and x = 1.85 (Answer)
