Answer:
0.66 mL are required for this neutralization
Explanation:
This is the neutralization equation
HCl + KOH → KCl + H₂O
When you neutralize, you make water like this:
HCl + H₂O → H₃O⁺ + Cl⁻
KOH → K⁺ + OH⁻
H₃O⁺ + OH⁻ ⇄ 2H₂O
Every time you neutralize, you have to apply this formula:
Nᵃ . Vᵃ = Nᵇ . Vᵇ
where N is normality and V volume
We also know that N . V = Gram equivalent
and N = M . valence
where in a base, valence means the quantity of OH inside the formula, and in an acid, valence means the quantity of H
In HCl, valence is 1 : in KOH is also 1
Gram equivalent is equal to mass in grams numerically equal to equivalent weight, where the equivalent weight (E) is the molar mass/valence
So 2.3 . Vᵃ = Nᵇ . Vᵇ
Vᵃ is our unknown.
So for the base, the Nᵇ . Vᵇ = gram-equivalent
Gram equivalent = Mass / E
E = molar mass / valence
Gram equivalent KOH = 85g / (56.1 g/m / 1)
Gram equivalent KOH = 1.51
2.3 . Vᵃ = 1.51
Vᵃ = 1.51 / 2.3 = 0.66 mL
