Answer:
ρ = 938.96 kg/m³
Explanation:
Given that
Weight of the ore in the air = 2 N
Weight of the ore in the water = 1.13 N
Lest take density of the ore = ρ
The volume of the ore = V
mass = Density x Volume
m= ρ V
In the air
m g = 2 = ρ V g
ρ V = 0.2 ----------1 ( take g= 10 m/s²)
The density of the water = 1000 kg/m³
In the water;
The bouncy force will act in the upward direction
bouncy force = Density of water x Volume x g
Weight = Fb - m g
1.13 = 1000 x V x g - 2
V= 2.13 x 10⁻⁴ m³ ------2
From equation 1 and 2
ρ x 2.13 x 10⁻⁴= 0.2
ρ = 938.96 kg/m³
Therefore the density of the ore is 938.96 kg/m³
Assumption :
We neglect the bouncy force due to air.
