The right answer is Option 2: [tex]\frac{7p^{15}}{3q^{12}}[/tex]
Step-by-step explanation:
Given expression is
[tex]\frac{28p^9q^{-5}}{12p^{-6}q^7}[/tex]
When the variables are same, the exponents of denominator are subtracted from the exponents of numerators;
[tex]=\frac{28p^{9-(6)}q^{-5-7}}{12}\\\\=\frac{28p^{9+6}q^{-12}}{12}\\\\=\frac{28p^{15}q^{-12}}{12}[/tex]
28 and 12 both are divisible by 4, therefore,
[tex]=\frac{7p^{15}q^{-12}}{3}[/tex]
For making the exponent of q positive,
[tex]=\frac{7p^{15}}{3q^{12}}[/tex]
The expression [tex]\frac{28p^9q^{-5}}{12p^{-6}q^7}[/tex] is equivalent to [tex]\frac{7p^{15}}{3q^{12}}[/tex]
The right answer is Option 2: [tex]\frac{7p^{15}}{3q^{12}}[/tex]
Keywords: linear expression, exponent
Learn more about exponents at:
- brainly.com/question/788903
- brainly.com/question/774670
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