The object has a positive acceleration
Explanation:
The graph in the question is missing; find it in attachment.
The acceleration of an object is defined as the rate of change in velocity of the object:
[tex]a=\frac{\Delta v}{\Delta t}[/tex]
where
[tex]\Delta v[/tex] is the change in velocity
[tex]\Delta t[/tex] is the change in time
We can verify that in a velocity-time graph, the acceleration corresponds to the slope of the graph. In fact, the slope is given by:
[tex]m=\frac{\Delta y}{\Delta x}[/tex]
where
[tex]\Delta y[/tex] is the change in the y-variable, so it is the change in velocity, [tex]\Delta v[/tex]
[tex]\Delta x[/tex] is the change in the x-variable, so it is the change in time, [tex]\Delta t[/tex]
Which means that the slope is equal to the acceleration:
[tex]m=\frac{\Delta y}{\Delta x}=\frac{\Delta v}{\Delta t}=a[/tex]
In this problem, the slope of the curve shown in the velocity-time graph in the figure is positive: therefore, this means that the object has a positive acceleration.
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Answer: It's "positive acceleration" I got the same question and got it right.
