Answer:
KO₂ and O₂ have 4:3 molar rato
Explanation:
Reaction Given
4KO₂+2CO₂→2K₂CO₃+3O₂
chemicals have a molar ratio of 4:3 = ?
Solution
First look at the Reaction
4KO₂ + 2CO₂-------→ 2K₂CO₃ + 3O₂
write the moles of the reactant and products that involve
4KO₂ + 2CO₂ -------→ 2K₂CO₃ + 3O₂
4 mol 2 mol 2 mol 3 mol
So the coefficients shows the number of moles of that compound involve in the reaction,
if we look for each ratio of moles to other
- 4 moles of KO₂ : 2 moles of CO₂
So the molar ratio of KO₂ to CO₂ is 4: 2
- 4 moles of KO₂ : 2 moles of K₂CO₃
So the molar ratio of KO₂ to K₂CO₃ is 4 : 2
- 2 moles of CO₂ : 2 moles of K₂CO₃
So the molar ratio of CO₂ to K₂CO₃ is 4 : 2
- 4 moles of KO₂ : 3 moles of O₂
So the molar ratio of KO₂ to O₂ is 4: 3
It is clear that KO₂ and O₂ are the chemicals in this reaction that are in the 4:3 molar ratio
