Respuesta :

Answer:

11025 W

Explanation:

Given that athlete can lift a mass of 900 kg by 2·5 m in 2 s

Average power output is defined as the work done per unit time

∴ Average power output = (work done) ÷ (time taken)

Here on the object the force that acts is the weight of that object

∴ Force on that object = (mass of the object) × (acceleration due to gravity) = 900 × 9·8 = 8820 N

∴ Person requires this much force to lift that object

Work done on the object is defined as the dot product of force and displacement

∴ Work done = 8820 × 2·5 =22050 J

Power = 22050 ÷ 2 = 11025 W

∴ Average power output of the athlete = 11025 W

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