Answer:
T= 4.24sec
Explanation:
We are going to use the formula below to calculate.
[tex]T=2\pi \sqrt{\frac{L}{g} }[/tex]
Where T is period
L is length of rod
g is acceleration due to gravity = [tex] 9.8m/s^{2}[/tex]
From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this [tex]L_{O}[/tex]
[tex]L_{O} = 3/4 * 5.95m[/tex]
= 4.4625m
thus [tex]T=2\pi \sqrt{\frac{L_{O} }{g} }[/tex]
[tex]T=2\pi \sqrt{\frac{4.4625 }{9.8} }[/tex]
T= 4.24sec
