A standard galvanic cell is constructed with Cu2+ | Cu and I2 | I- half cell compartments connected by a salt bridge. Which of the following statements are correct?Hint: Refer to a table of standard reduction potentials.(Choose all that apply.)I2 is reduced at the cathode.I- is oxidized at the anode.The anode compartment is the Cu2+|Cu compartment.In the external circuit, electrons flow from the Cu2+|Cu compartment to the I2|I- compartment.As the cell runs, anions will migrate from the Cu2+|Cu compartment to the I2|I- compartment.

Respuesta :

Answer: The correct statement are following.

  • [tex]I_{2}[/tex] is reduced at the cathode.
  • In the external circuit, electrons flow from the [tex]Cu^{2+}|Cu[/tex] compartment to the [tex]I2|I^{-}[/tex] compartment.

Explanation:

An oxidizing agent is defined as a substance which readily accepts an electron and itself gets reduced in order to oxidize another substance in a chemical reaction.

So, as per the given data the reaction equations are as follows.

  [tex]Cu^{2+} + 2e^{-} \rightarrow Cu(s)[/tex],    [tex]E_{o}[/tex] = +0.337

  [tex]I_{2}(s) + 2e^{-} \rightarrow 2I[/tex],   [tex]E_{o}[/tex] = +0.54

Lower or less negative is the [tex]E_{o}[/tex] value, more easily the element or substance can lose electrons. This means that the element itself gets oxidized and reduces the other element or substance.

As per the given data, [tex]I^{-}[/tex] electrode acts as cathode and [tex]Cu^{-}[/tex] electrode acts as anode.

  • Hence, [tex]I_{2}[/tex] is reduced at cathode. And, the anode compartment is [tex]Cu^{2+}|Cu[/tex] compartment.
  • Also, in the external circuit electrons flow from [tex]Cu^{2+}|Cu[/tex] to the [tex]I_{2}|I^{-}[/tex] compartment.