Answer:
The first graph is the appropriate graph for the given equation.
The graph is attached below.
Step-by-step explanation:
Given,
[tex]y+6= \frac{3}{4}(x+4)[/tex]
This represents the equation of a straight line of the form
[tex]y-y1 = m(x-x1)[/tex]
Where [tex]m[/tex] is slope and [tex](x1,y1)[/tex] is one of the point on the graph through which the line crosses.
On comparing the given equation with the original form we deduce that
[tex](-4,-6)[/tex] is one of the point.
And [tex]\frac{3}{4}[/tex] is the slope, which is positive. A positive slope represents a line inclined to the right side.
Let us observe all the graphs now!
We deduce that first graph is the appropriate graph for the given equation.
