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(a) Calculate the absolute pressure at the bottom of a fresh-water lake at a depth of 28.8 m. Assume the density of the water is 1.00 ✕ 103 kg/m3 and the air above is at a pressure of 101.3 kPa.

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Answer:

383828 Pa

Explanation:

[tex]P_0[/tex] = Atmospheric pressure = [tex]101.3\times 10^3\ Pa[/tex]

[tex]\rho[/tex] = Density of water = 1000 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth = 28.8 m

Absolute pressure is given by

[tex]P=P_0+\rho gh\\\Rightarrow P=101.3\times 10^3+1000\times 9.81\times 28.8\\\Rightarrow P=383828\ Pa[/tex]

The absolute pressure at the bottom of the fresh water lake is 383828 Pa

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