Respuesta :
Answer:
The total pressure in the container at equilibrium is 0.37065 atm
Explanation:
Step 1: Data given
Kp for the decomposition of H2S is 0.795
Only H2S is present at a pressure of 0.203 atm
Step 2: The balanced equation
H2S (g) → H2(g) + S(g)
Step 3: Calculate partial pressure of H2 and S
Initially, there is no H2 and S, they have no pressure
There will react X
The pressure at the equilibrium we have:
H2: X
S: X
H2S: 0.203 - X
Kp = (pH2)(pS)/(pH2S)
0.795 = (x)(x)/(0.203 - X)
X = 0.16765
Step 4: Calculate total pressure at equilibrium:
Total pressure = the partial pressure of H2 + partial pressure of S + partial pressure of H2S
P = X + X + (0.203 - X)
P = 0.16765 + 0.16765 + (0.203 - 0.16765)
P = 0.37065 atm
The total pressure in the container at equilibrium is 0.37065 atm
