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You are holding a bulletin board weighing w = 4.00 N in place against a wall while your friend secures it to the wall. To keep it from slipping, you apply a force P perpendicular to the bulletin board, pressing it directly into the wall. How large must this force be if the coefficient of static friction with the wall is 0.450?

Respuesta :

Answer:

the force must be equal to 8.888 N to keep it from slipping

Explanation:

We have given weight of the bulletin board W = mg =4 N

Coefficient of static friction [tex]\mu =0.450[/tex]

When frictional force balance the weight

Then [tex]\mu N=mg[/tex]

So [tex]0.450\times N=4[/tex]

[tex]N=\frac{4}{0.450}=8.888N[/tex]

So the force must be equal to 8.888 N to keep it from slipping

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