Answer:
A=8cm (Shortest)
B= 14cm
C = 18 cm (longest)
The longest side is 10 cm bigger than the shortest side
Step-by-step explanation:
Let sides of a triangle be,
A, B and C
A be the short side
and C be the longest side
Perimeter = Sum of all sides = A+B+C = 40 cm
Using information given:
The length of the longest side is four cm less than the sum of th lengths of the other sides. The length of the shortest side is four cm more than the difference between the lengths of the other sides.
C = (A+B) -4
A = 2 (C-B)
rearrange:
A+B+C = 40 ----------------Equation 1
A+B-C = 4 ------------------ Equation 2
A+2B-2C = 0 -------------------- Equation 3
Equation 1 + Equation 2 :
2 (A+B) = 44
A+B = 22 ,
put in Equation 1 :
22 + C = 40
C = 18 cm
As A+B = 22 ,
we can write :
A = 22 -B
Put in Equation 3
22 - B + 2B - 2C = 0
B-2C = - 22
B = - 22 + 2C
B = - 22 + 36
B =14 cm
put value of B in A+B = 22
A + 14 = 22
A = 8 cm
Results:
A=8cm
B= 14cm
C = 18 cm
Here A is the shortest and C is the longest side,
So C-A = 18 - 8 = 10cm
The longest side is 10 cm bigger than the shortest
Answer:
10
Step-by-step explanation:
40=2a-3+2a+3a+1
Add like terms.
40=7a-2
Get 'a' by itself.
40(+2)=7a-2(+2) [2 cancels out]
42(÷7)=7a(÷7) [7 cancels out]
a=6
Plug in the answer for equations.
Biggest: 3(6)+1= 18+1= 19
Smallest: 2(6)-3= 12-3=9
Subtract the smallest from the biggest.
19-9=10
