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A garden hose with a small puncture is stretched horizontally along the ground. The hose is attached to an open water faucet at one end and a closed nozzle at the other end. As you might suspect, water pressure builds up and water squirts vertically out of the puncture to a height of 0.93 m. Determine the pressure inside the hose. (Enter your answer to the nearest 1000 P

Respuesta :

Answer:110.439 KPa

Explanation:

Given

Height to which water is raised [tex]h=0.93 m[/tex]

assuming [tex]P_{atm}=101.325 KPa[/tex]

Applying Bernoulli's equation between Pipe Puncture and highest Point we get

[tex]P_1+0.5\rho v_1^2+\rho gh_1=P_2+0.5\rho v_2^2+\rho gh_2[/tex]

[tex]v_1=0,h_1=0,v_2=0[/tex]

we get

[tex]P_1-P_{atm}=\rho gh[/tex]

[tex]\Delta P=10^3\times 9.8\times 0.93[/tex]

[tex]P_1=P_{atm}+9.114[/tex]

[tex]P_1=101.325+9.114=110.439 KPa[/tex]

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