Use Euler's Theorem to calculate how many vertices a polyhedron has if it has 6 faces and 12 edges.

8 veretices
12 vertices
18 vertices
6 vertices

Respuesta :

[tex]v+f-e=2\\ v=2-f+e\\ v=2-6+12\\ v=8[/tex]
caylus
Hello,

E=V+F-2 with
E number of edges
F number of faces
V number of vertices;

So V=E-F+2=12-6+2=8

Your polyhedron is a cube. (or a "parrallélipipède ")