Answer:
Step-by-step explanation:
[tex]\text{The slope-intercept form of an equation of a line:}\\\\y=mx+b\\\\m-\text{slope}\\b-\text{y-intercept}\\\\\text{Let}\\\\k:y=m_1x+b_1\\l:y=m_2x+b_2\\\\k\ \perp\ l\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\k\ ||\ l\iff m_1=m_2\\=========================[/tex]
[tex]\text{We have}\ y=5x+2\to m_1=5\\\\\text{therefore}\ m_2=5.\\\\\text{Put the value of the slope and the coordinates of the given point (-2, 1)}\\\text{to the equation of a line:}\\\\1=5(-2)+b\\1=-10+b\qquad\text{add 10 to both sides}\\1+10=-10+10+b\\11=b\to b=11\\\\\text{Finally:}\\\\y=5x+11[/tex]
