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in a hydraulic press the small cylinder has a diameter 10.0cm while the large has 25cm if the force of 600N is applied to the small cylinder. find the force exacted on the large cylinder

Respuesta :

MathPhys

Answer:

3750 N

Explanation:

Pressure on the small cylinder = pressure on the large cylinder

P₁ = P₂

F₁ / A₁ = F₂ / A₂

F₁ / (π d₁² / 4) = F₂ / (π d₂² / 4)

F₁ / d₁² = F₂ / d₂²

600 N / (10.0 cm)² = F / (25.0 cm)²

F = 3750 N

aabdulsamir

Answer:

3751.34N

Explanation:

Pressure in large piston = pressure in smaller piston

P2 = P1

Pressure = Force / Area

Area = pi * r²

r1= d1/2 = 10/ 2 = 5cm = 0.05m

Area(A1) = 22/7 * (0.05)² = 0.00785m²

r2 = d2 / 2 = 25/2 = 12.5cm = 0.125m

Area(A2) = 22/7 * (0.125)² = 0.04908m²

Pressure = Force / Area

F1/A1 = F2/A2

600 / 0.00785 = F2 / 0.04908

F2 = (600 * 0.04908) / 0.00785

F2 = 3751.34N

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