Question:
1. (NH)2CrO
a) Number of moles of H:
b) Number of moles of N:
Answer:
a) Number of moles of H: 2
b) Number of moles of N: 2
Explanation:
The [tex](NH)_2CrO[/tex] is ammonium Chromate which is monoclinic and yellow Crystal that is formed due to the reaction of ammonium Hydroxide and ammonium di-chromate. It is used as catalyst, corrosion inhibitor as well as analytical inhibitors.
Question:
2. Ag.SO.
a) Molar Mass:
b) Percent Composition of Ag:
c) Percent Composition of S:
d) Percent Composition of O:
Answer:
a) Molar Mass: 155.93 Kg
b) Percent Composition of Ag: 69%
c) Percent Composition of S: 20.5%
d) Percent Composition of O: 10.2%
Explanation:
Molar mass = molar mass of Ag + molar mass of S + molar mass of O
=>107.87+32.06+16
=> 155.93 Kg
Percent Composition of Ag
= [tex]\frac{ \text{mass due to Ag}}{\text {total molar mass}} \times 100[/tex]
= [tex]\frac{107.87}{155.93} \times 100[/tex]
= 0.69 \times 100
= 69%
Percent Composition of S:
= [tex]\frac{ \text{mass due to S}}{\text {total molar mass}} \times 100[/tex]
=[tex]\frac{32.06}{155.93} \times 100[/tex]
= 0.205 \times 100
= 20.5%
Percent Composition of O:
= [tex]\frac{ \text{mass due to O}}{\text {total molar mass}} \times 100[/tex]
= [tex]\frac{16.00}{155.93} \times 100[/tex]
= 0.102 \times 100
= 10.2%
