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On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above and to the left of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-thirdx − 1 y ≥ One-thirdx − 1 y < 3x − 1 y > 3x − 1On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above and to the left of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-thirdx − 1 y ≥ One-thirdx − 1 y < 3x − 1 y > 3x − 1

Respuesta :

calculista

Answer:

[tex]y\geq\frac{1}{3}x-1[/tex]

Step-by-step explanation:

A solid straight line has a positive slope and goes through (0, negative 1) and (3, 0)

Find the slope of the solid line

[tex]m=(0+1)/(3-0)\\\\m=\frac{1}{3}[/tex]

The equation of the solid line in slope intercept form is equal to

[tex]y=mx+b[/tex]

we have

[tex]m=\frac{1}{3}[/tex]

[tex]b=-1[/tex] ---> given problem

substitute

[tex]y=\frac{1}{3}x-1[/tex]

Everything above and to the left of the line is shaded

so the inequality is equal to

[tex]y\geq\frac{1}{3}x-1[/tex]

lexisixela

Answer:

Step-by-step explanation:

its B just took the quiz

y ≥ One-thirdx − 1

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