Question 20. SQ is an angle bisector. Find the value of x. Please help!! Struggling

Answer:
The value of x is 6.
Step-by-step explanation:
Given:
∠TSQ = (5x + 3)°
∠RSQ = (10x - 27)°
SQ is the angle bisector of ∠ TSR
To Find:
x = ?
Solution:
Angle Bisector:
A line that splits an angle into two equal angles.
'Bisect' means to divide into two equal parts.
SQ is the angle bisector of ∠ TSR ....Given
∴ [tex]\angle TSQ=\angle RSQ[/tex]
Substituting the values we get
[tex](5x+3)=(10x-27)\\\\10x-5x=27+3\\\\5x=30\\\\\therefore x=\dfrac{30}{5}=6\\\therefore x=6[/tex]
The value of x is 6.