Respuesta :
Answer:
81 x 10^6
Step-by-step explanation:
x0000000
11111111x
22222222
33333333
....................
88888888
99999999
---------------------
The first digit and 8th digit column has only 9 numbers and the rest 6 column have 10 possible numbers
9 x 9 x 10^6 = 81 x 10^6
For given conditions, the total number of possible digits is 81000000 = 81 million digits.
How do you find total count of such 8 digit numbers?
In total we have 10 digits as: 0,1,2,3,4,5,6,7,8,9.
The restrictions are given as
- Number size = 8
- First digit can't be 0
- Last digit can't be 1
We will use those digits to form the whole 8 digits number. Thus, using those digits 8 times.
Thus, we have:
First digit chooses from remaining 9 digits
All middle 6 digits chooses from 10 digits.
The last digit can choose from 9 digits.
Using the rule of product from combinatorics
Total count of possible digits = [tex]9 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 9 = 81000000[/tex]
Thus, in total, on the given conditions, total 81 million digits can be formed.
Learn more about combinations related topics here:
https://brainly.com/question/13932562
