A parent is buying two types of chocolate truffles for the children. The oldest child likes white chocolate (W), the younger two children like dark chocolate (D) and the spouse likes white chocolate (W). Four white chocolate truffles (W) cost the same as three dark chocolate truffles (D). If the parent bought 3 white chocolate truffles(W) and 6 dark chocolate truffles (D), and spent $49.50, how much was each dark chocolate truffle?

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joaobezerra joaobezerra · Answer 1 · 2020-01-08T04:32:17+01:00

Answer:

Each dark chocolate tuffle was $6.

Step-by-step explanation:

This question can be solved by a system of equations.

Four white chocolate truffles (W) cost the same as three dark chocolate truffles (D).

So [tex]4W = 3D[/tex]

The parent bought 3 white chocolate truffles(W) and 6 dark chocolate truffles (D), and spent $49.50.

[tex]3W + 6D = 49.50[/tex]

[tex]4W = 3D[/tex]

So

[tex]D = \frac{4W}{3}[/tex]

[tex]3W + 6D = 49.50[/tex]

[tex]3W + 8W = 49.50[/tex]

[tex]11W = 49.5[/tex]

[tex]W = 4.5[/tex]

[tex]D = \frac{4W}{3} = \frac{4*4.5}{3} = 6[/tex]

Each dark chocolate tuffle was $6.

Favouredlyf Favouredlyf · Answer 2 · 2020-01-08T08:59:30+01:00

Answer:the cost of each dark chocolate truffle is $6

Step-by-step explanation:

Let W represent the cost of each white chocolate truffle.

Let D represent the cost of each dark chocolate truffle.

Four white chocolate truffles (W) cost the same as three dark chocolate truffles (D). This means that

4W = 3D

If the parent bought 3 white chocolate truffles(W) and 6 dark chocolate truffles (D), and spent $49.50. It means that

3W + 6D = 49.5 - - - - - - - - - -1

Substituting W = 3D/4 into into equation 1, it becomes

3(3D/4) + 6D = 49.5

2.25D + 6D = 49.5

8.25D = 49.5

D = 49.5/8.25 = 6

Substituting D = 6 into

W = 3 × 6/4 = 4.5