A box weighing 20 newtons is to be pushed across a smooth floor with a horizontal force of 5 Newtons. What acceleration will be produced?

Respuesta :

The acceleration of the box is [tex]2.45 m/s^2[/tex]

Explanation:

The weight of the box is given by:

[tex]W=mg[/tex]

where here we have

W = 20 N is its weight

m is the mass of the box

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

Solving for m, we find the mass of the box:

[tex]m=\frac{W}{g}=\frac{20}{9.8}=2.04 kg[/tex]

Now we can apply Newton's second law, which states that the net force on the box is equal to the product between its mass and its acceleration:

[tex]F=ma[/tex]

where:

F = 5 N is the force applied to the box

m = 2.04 kg is the mass

a is the acceleration

Solving for a, we find:

[tex]a=\frac{F}{m}=\frac{5}{2.04}=2.45 m/s^2[/tex]

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