Write a quadratic equation to represent a function with the following vertex. Use a leading coefficient
other than 1.
a. (100, 200)
b. (− 3 / 4 , −6)

Respuesta :

Answer:

a. [tex]y=5(x-100)^2+200[/tex]

b. [tex]y=-2(x+\frac{3}{4})^2-6[/tex]

Step-by-step explanation:

the equation of a quadratic function in the vertex form is:

[tex]y=a(x-h)^2+k[/tex]

where [tex]a[/tex] is the leading coefficient, and [tex](h,k)[/tex] is the vertex.

  • for a:

we have the vertex [tex](100,200)[/tex] so [tex]h=100[/tex] and [tex]k=200[/tex], thus the equation is:

[tex]y=a(x-100)^2+200[/tex]

and you can choose any value for [tex]a[/tex] other than 1. I will choose 5:

[tex]y=5(x-100)^2+200[/tex]

  • for b:

we have the vertex [tex](\frac{-3}{4}, -6)[/tex] so [tex]h=\frac{-3}{4}[/tex] and [tex]k=-6[/tex], thus the equation is:

[tex]y=a(x-(-\frac{3}{4}))^2+(-6)[/tex]

[tex]y=a(x+\frac{3}{4})^2-6[/tex]

and you can choose any value for [tex]a[/tex] other than 1. I will choose -2 this time:

[tex]y=-2(x+\frac{3}{4})^2-6[/tex]