Answer:
The coordinates of the intersection of the medians of △ABC is (1/3, 1).
Step-by-step explanation:
Consider the vertices of △ABC are A(2, 4), B(−4, 0), and C(3, −1).
Intersection of the medians of a triangle is known as centroid.
Formula for centroid of a triangle is
[tex]Centroid=(\dfrac{x_1+x_2+x_3}{3},\dfrac{y_1+y_2+y_3}{3})[/tex]
Using the above formula the centroid of △ABC is
[tex]Centroid=(\dfrac{2-4+3}{3},\dfrac{4+0-1}{3})[/tex]
[tex]Centroid=(\dfrac{1}{3},\dfrac{3}{3})[/tex]
[tex]Centroid=(\dfrac{1}{3},1)[/tex]
Therefore the coordinates of the intersection of the medians of △ABC is (1/3, 1).
