Answer:
0.04651 N
Explanation:
[tex]F_1[/tex] = Force on plunger = 2.29 N
[tex]d_1[/tex] = Diameter of plunger = 1.27 cm
[tex]d_2[/tex] = Diameter of needle = 0.181 cm
[tex]F_2[/tex] = Force on needle
From Pascal's law we have
[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\Rightarrow F_2=\dfrac{F_1\times A_2}{A_1}\\\Rightarrow F_2=\dfrac{2.29\times \pi\dfrac{0.181^2}{4}}{\dfrac{\pi 1.27^2}{4}}\\\Rightarrow F_2=0.04651\ N[/tex]
The force with which the fluid leaves the needle is 0.04651 N
