Answer:
Fractions of total kinetic energy in the form of rotational
kinetic energy about the center of mass = 2/5
Explanation:
Moment of Inertia for a thin walled spherical Shell, I = (2/3)*m*r^2
Translational Kinetic Energy = (1/2)*m*v^2
Rotational Kinetic Energy = (1/2)*(I)*(w^2)
Angular Velocity, w = v/r, where v is the linear velocity
Rotational Kinetic Energy = (1/2)*( (2/3)*m*r^2)*((v/r)^2)
Rotational Kinetic Energy = (1/3)*m*v^2
Total Kinetic Energy = (1/3 + 1/2)*m*v^2
Total Kinetic Energy = (5/6)*m*v^2
Fraction = Rotational Kinetic Energy/ Total Kinetic Energy
Fraction = ((1/3)*m*v^2)/ ((5/6)*m*v^2)
Fraction = 2/5
