Respuesta :
Answer:
The total time is 41.38 hours.
Explanation:
Given that,
Mass 230 kg
Mass of water = 830 kg
Temperature = 18 C
Rate of energy supplied = 52000 Kj/h
Let the boiling temperature of the water be 100°C
(a). We need to calculate the energy
So from the principle of calorimeter
[tex]m_{b}C_{i}(T_{b}-T_{i})+m_{w}C_{w}(T_{b}-T_{i})=Q_{i}[/tex]
Put the value into the formula
[tex]230\times450+830\times4186(100-18)=Q_{i}[/tex]
[tex]Q_{i}=285002660\ J[/tex]
[tex]Q_{i}=2.85\times10^{8}\ J[/tex]
We need to calculate the time
Using formula of energy
[tex]Q_{i}=Pt[/tex]
[tex]t=\dfrac{Q_{i}}{P}[/tex]
Put the value into the formula
[tex]t=\dfrac{2.85\times10^{8}}{52000\times10^{3}}[/tex]
[tex]t=5.48\ hours[/tex]
(b). There is no change in temperature.
So the additional heat required to change the water into steam is
We need to calculate the energy
Using formula of energy
[tex]Q=m_{w}L_{s}[/tex]
[tex]Q=830\times22.6\times10^{5}[/tex]
[tex]Q=1.87\times10^{9}\ J[/tex]
We need to calculate the additional time
Using formula of additional time
[tex]t'=\dfrac{Q}{P}[/tex]
Put the value into the formula
[tex]t'=\dfrac{1.87\times10^{9}}{52000\times10^{3}}[/tex]
[tex]t'=35.9\ hours[/tex]
We need to calculate the total time
Using formula of time
[tex]t''=t+t'[/tex]
Put the value into the formula
[tex]t''=5.48+35.9[/tex]
[tex]t''=41.38\ hours[/tex]
Hence, The total time is 41.38 hours.
