Answer:
The fraction is less than [tex]\frac{17}{18}[/tex].
Step-by-step explanation:
Let the fraction is [tex]\frac{1}{n}[/tex].
Given that when the fraction of 17 is subtracted from 17 itself, then the remaining will be greater than one-third of 17 divided by six.
Therefore, by the given condition,
[tex]17 - \frac{17}{n} > \frac{1}{3}(\frac{17}{6} )[/tex]
⇒ [tex]17 - \frac{17}{n} > \frac{17}{18}[/tex]
⇒ [tex]1 - \frac{1}{n} > \frac{1}{18}[/tex]
⇒ [tex]\frac{1}{n} < 1 - \frac{1}{18}[/tex]
⇒ [tex]\frac{1}{n} < \frac{17}{18}[/tex]
Therefore, the fraction is less than [tex]\frac{17}{18}[/tex]. (Answer)
