Answer:
L = 1.25 x 10⁸ kg.m²/s
Explanation:
given,
mass of airplane (m)= 1200 Kg
speed of the flight (v)= 80 m/s
distance (r)= 1.3 Km
= 1300 m
angular momentum = ?
L = m v r
L =1200 x 80 x 1.3 x 1000
L = 124800000 kg.m²/s
L = 1.25 x 10⁸ kg.m²/s
hence,the magnitude of angular momentum with respect to a point on the ground is equal to L = 1.25 x 10⁸ kg.m²/s
The angular momentum when a 1200 kg airplane is flying in a straight line at 80 m/s, 1.3km above the ground =
Angular momentum: This is the product of mass or inertia and angular velocity. The s.i unit is kgm²/s. = 124800000 kgm²/s
From the question,
The Formula of angular momentum is
M' = mvr................... Equation 1
Where M' = angular momentum, m = mass of the airplane, v = linear velocity, r = radius.
Given: m = 1200 kg, v = 80 m/s, r = 1.3 km = 1300 m
Substitute these values into equation 1
M' = 1200(80)(1300)
M' = 124800000 kgm²/s
Hence the magnitude of the angular momentum is 124800000 kgm²/s
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