Answer:
X = 0.005%
Explanation:
The concentration of X remaining in the water phase can be calculated using the next equation:
[tex] [X]_{i} = (\frac{V_{aq}}{V_{or}KD + V_{aq}})^{i} \cdot [X_{0}] [/tex]
Where:
[tex]X_{i}[/tex]: is the concentration of A remaining in aqueous solution
[tex]V_{aq}[/tex]: is the volume of water
[tex]V_{or}[/tex]: is the volume of the organic solvent
KD: is the distribution constant of X between water and the organic solvent
[tex]X_{0}[/tex]: is the original concentration of X
i: is the number of extractions with the organic solvent
[tex] [X]_{i} = (\frac{50 mL}{10 mL \cdot 13.5 + 50 mL})^{4} \cdot 0.01 M = 5.34 \cdot 10^{-5} M [/tex]
The percent of X remaining in the water phase is:
[tex] [X]_{i} = 5.34 \cdot 10^{-5} \cdot 100 \% = 0.005 \% [/tex]
I hope it helps you!
