Respuesta :
Answer:
The distance cover by teacher in 30 minutes is 4[tex]\dfrac{1}{6}[/tex] miles .
Step-by-step explanation:
Given as :
The distance cover by student = d = 3[tex]\dfrac{1}{3}[/tex] miles
i.e d = [tex]\dfrac{10}{3}[/tex] miles
The time taken by student to cover [tex]\dfrac{10}{3}[/tex] miles distance = t = 30 minutes
Let The speed of student = s miles per minute
∵ Speed = [tex]\dfrac{\textrm Disatnce}{\textrm Time}[/tex]
Or, s = [tex]\dfrac{d}{t}[/tex]
Or, s = [tex]\frac{\frac{10}{3}}{30}[/tex]
i.e s = 0.111 miles per min
So, The speed of student = s = 0.111 miles per min
Now, Again
The speed of teacher = 1[tex]\dfrac{1}{4}[/tex] times as fast as student
Let The speed of teacher = S miles per min
∵ The speed of teacher = [tex]\dfrac{5}{4}[/tex] × speed of student
So, S = [tex]\dfrac{5}{4}[/tex] × s
Or, S = [tex]\dfrac{5}{4}[/tex] × 0.111 miles per min
Or, S = [tex]\frac{5\times 0.111}{4}[/tex] mil/min
i.e, S = 0.13875 miles per min
So, The speed of teacher = S = 0.13875 miles per min
Let The distance cover by teacher = D miles
The time taken by teacher to cover D miles distance = T = 30 minutes
∵ Distance = Speed × Time
Or, D = S × T
Or, D = 0.13875 miles per min × 30 min
∴ D = 4.1625 miles
i.e D = 4[tex]\dfrac{1}{6}[/tex] miles
So, The distance cover by teacher in 30 minutes = D = 4[tex]\dfrac{1}{6}[/tex] miles
Hence,The distance cover by teacher in 30 minutes is 4[tex]\dfrac{1}{6}[/tex] miles . Answer
