If the measure of angle BCD=51 degrees, solve for x.

Answer:
[tex]x=5[/tex]
Step-by-step explanation:
step 1
Find the measure of angle EFD
In this problem I will assume that ABCD is a parallelogram
In a parallelogram opposite angles are congruent and consecutive angles are supplementary
so
[tex]m\ angle BCD=m\angle BED=51^o[/tex]
[tex]m\ angle FED=(1/2)m\angle BED=(1/2)51^o=25.5^o[/tex] --- > given problem
Remember that the sum of the interior angles in any triangle must be equal to 180 degrees
so
In the triangle EFD
[tex]m\ angle FED+m\ angle FDE+m\ angle EFD=180^o[/tex]
substitute the given values
[tex]25.5^o+55^o+m\ angle EFD=180^o[/tex]
[tex]80.5^o+m\ angle EFD=180^o[/tex]
[tex]m\ angle EFD=180^o-80.5^o[/tex]
[tex]m\ angle EFD=99.5^o[/tex]
step 2
Find the measure of angle EFB
we know that
[tex]m\angle EFB+m\angle EFD=180^o[/tex] ---> by supplementary angles
we have
[tex]m\ angle EFD=99.5^o[/tex]
substitute
[tex]m\angle EFB+99.5^o=180^o[/tex]
[tex]m\angle EFB=180^o-99.5^o[/tex]
[tex]m\angle EFB=80.5^o[/tex]
step 3
Find the value of x
Remember that the sum of the interior angles in any triangle must be equal to 180 degrees
so
In the triangle EBF
[tex]m\ angle BEF+m\ angle EFB+m\ angle EBF=180^o[/tex]
we have
[tex]m\angle BEF=m\ angle FED=25.5^o[/tex]
[tex]m\angle EFB=80.5^o[/tex]
[tex]m\angle EBF=(14x+4)^o[/tex]
substitute
[tex]25.5^o+80.5^o+(14x+4)^o=180^o[/tex]
solve for x
Combine like terms
[tex](14x+110)^o=180^o[/tex]
[tex]14x=180-110[/tex]
[tex]14x=70[/tex]
[tex]x=5[/tex]
The value of x is = 5
Suppose that BCDE is a parallelogram.
According to the given question ;
In a parallelogram Opposite sides are congruent. Opposite angles are congruent. Consecutive angles are supplementary. The diagonals bisect each other.
So ,
m∠BCD= m∠BED = 51°
m∠FED = [tex]\frac{1}{2} m[/tex]∠BED
= [tex]\frac{1}{2} ( 51 )[/tex]
= 25.5 °
Remember that the sum of the all interior angles in any triangle must be equal to 180° degrees.
m∠FED + m∠FDE + m∠EFD = 180°
22.5° + 55° + m∠EFD = 180°
m∠EFD = 180° - 80.5°
m∠EFD = 99.5°
Now,
TO find measure of angle EFB
we know that
m∠EFP + m∠EFD = 180°
By supplementary angles The two angles are said to be supplementary angles when they add up to 180°.
we have,
m∠EFD =99.5°
Substitute
m∠EFB + 99.5° = 180°
m∠EFB = 80.5°
Again by the property the sum of all the interior angle in the angle is 180°
In the,
m∠BEF + m∠EFB + m∠EBF = 180°
we have
m∠BEF = m ∠FED = 25.5°
m∠EFB = 80.5°
m∠EBF = ( 14x + 4 )°
substitute the values
25.5 + 80.5 + ( 14x+4) = 180
106 + 14x + 4 = 180
110 + 14x = 180
14x = 180-110
14x = 70
x =[tex]\frac{70}{14}[/tex]
x = 5
The value of x is 5 .
For the more information about parallelogram properties click the link given below .
https://brainly.com/question/22106495