Answer:[tex]10.815 kg-m^2[/tex]
Explanation:
Given
mass of object [tex]m=3 kg[/tex]
Moment of Inertia of Irregular about an axis passing through an axis [tex]r=1.05\ m[/tex] from its center of mass
From parallel axis theorem, the moment of inertia about an axis parallel to an axis passing through the center of mass is equal to the sum of moment of inertia about the center of mass and product of mass and square of the distance of required axis from the center of the mass axis.
[tex]I=I_{com}+mr^2[/tex]
[tex]I_{com}=7.508\ kg-m^2[/tex]
[tex]mr^2=3\times (1.05)^2=3.307\ kg-m^2[/tex]
[tex]I=7.508+3.307=10.815\ kg-m^2[/tex]
