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A friend of yours is loudly singing a single note at 403 Hz while racing toward you at 26.3 m/s on a day when the speed of sound is 340 m/s .What frequency do you hear?What frequency does your friend hear if you suddenly start singing at 403?

Respuesta :

Answer:

Explanation:

Given

Natural frequency of vibration [tex]f=403\ Hz[/tex]

Velocity of source [tex]v_s=26.3\ m/s[/tex]

Considering velocity of sound [tex]v=341\ m/s[/tex]

Apparent Frequency of sound is given by Doppler effect

[tex]f'=\frac{v+v_o}{v-v_s}\cdot f[/tex]

where [tex]f=natural\ frequency[/tex]

[tex]v=velocity\ of\ sound\ wave[/tex]

[tex]v_o=velocity\ of\ observer[/tex]

[tex]v_s=velocity\ of\ source[/tex]

[tex]f'=apparent\ frequency[/tex]

here [tex]v_o=0[/tex]

[tex]f'=\frac{341}{341-26.3}\cdot 403=437.37 Hz[/tex]

If you start singing at frequency of 403 Hz then apparent frequency to your friend

Observer is moving with 26.3 m/s and source is stationary

[tex]f'=\frac{v+26.3}{v-0}\cdot 403[/tex]

[tex]f'=\frac{341+26.3}{341}\cdot 403=434.08\ Hz[/tex]                                              

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