Answer:
86 cm
Step-by-step explanation:
We are given that
Billiard ball travels before ricocheting off a rail=100 cm
After ricocheting ball travels=120 cm
The angles between the path as the ball approaches the rail and the path after strikes the rail=45 degrees
We have to find the distance between corner pocket from where cue initially struck the ball.
Cosine law:[tex]c^2=\sqrt{a^2+b^2-abcos\theta}[/tex]
By using cosine law
[tex]AB=\sqrt{AC^2+BC^2-2(AC)(BC)Cos45}[/tex]
[tex]AB=\sqrt{(100)^2+(120)^2-2(100)(120)\times \frac{1}{\sqrt 2}}[/tex]
[tex]AB=86[/tex]cm
Hence, the distance of cornet pocket form where the cue initially struck the ball=86 cm
