Two trains start from Fort Worth traveling at the same speed. The trip for Train W takes 20 hours, while the trip for Train Z takes 25 hours. If the city Train Z is traveling to is 400 miles farther away than the city Train W is traveling to, how far will each train travel in total to reach its destination?

Which of the following rational equations best models this situation?

a. x/25 = x+400/20

b. x/20 = x+400/25

c. x/20 = x/25 - 400

d. x/20 = x-400/25

e. x/20 + 400 = x/25

Respuesta :

Answer:

The equation that best models this situation is :

b. [tex]\frac{x}{20}=\frac{x+400}{25}[/tex]

Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = 2,000 miles

Step-by-step explanation:

Given:

Time taken for Train W to complete a trip = 20 hours

Time taken for Train Z to complete a trip = 25 hours

The city Train Z is traveling to is 400 miles farther away than the city Train W is traveling to.

both trains have same speeds and start from same location.

To find the distance in total each train travels.

Solution:

Let length of the trip of Train W be = [tex]x[/tex] miles

Speed of Train W can be given as :

⇒ [tex]\frac{Distance}{Time}[/tex]

⇒ [tex]\frac{x}{20}\ miles/h[/tex]

So, the length of the trip of Train Z will be = [tex](x+400)[/tex] miles

Speed of Train Z can be given as :

⇒ [tex]\frac{Distance}{Time}[/tex]

⇒ [tex]\frac{x+400}{25}\ miles/h[/tex]

Since the speeds are same, so the equation to find [tex]x[/tex] can be given as:

⇒ [tex]\frac{x}{20}=\frac{x+400}{25}[/tex]

Solving for [tex]x[/tex]

Multiplying both sides by 100 to remove fractions.

⇒ [tex]100\times \frac{x}{20}=100\times \frac{x+400}{25}[/tex]

⇒ [tex]5x=4(x+400)[/tex]

Using distribution.

⇒ [tex]5x=4x+1600[/tex]

Subtracting both sides by [tex]4x[/tex]

⇒ [tex]5x-4x=4x-4x+1600[/tex]

⇒ [tex]x=1600[/tex]

Thus, Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = [tex]1600+400[/tex] = 2,000 miles

The following rational equations best model this situation is;

[tex]\rm \dfrac{x}{20}= \dfrac{x+400}{25}\\\\[/tex], the correct option is B.

The distance covered by each train travel in total to reach its destination is 2000 miles.

The distance covered train W is 1600.

Given

Time is taken for Train W to complete a trip = 20 hours

Time is taken for Train Z to complete a trip = 25 hours

What is the relation between distance and speed?

The relation between distance and speed is given by;

[tex]\rm Speed = \dfrac{Distance}{Time}[/tex]

Let, the length of the trip of Train W be x.

The length of the trip of Train Z is (x+400).

Then,

The Speed of Train W is given by;

[tex]\rm Speed \ W = \dfrac{Distance}{Time}\\\\ Speed \ W = \dfrac{x}{20}[/tex]

And Speed of Train Z is given by;

[tex]\rm Speed \ Z = \dfrac{Distance}{Time}\\\\ Speed \ Z = \dfrac{x+400}{25}[/tex]

Therefore,

The following rational equations best model this situation is;

[tex]\rm \dfrac{x}{20}= \dfrac{x+400}{25}\\\\25x=20(x+400)\\\\ 25x=20x+8000\\\\25x-20x=8000\\\\5x=8000\\\\x=\dfrac{8000}{5}\\\\x=1600[/tex]

The distance covered train W is 1600.

The distance covered by each train travel in total to reach its destination is;

= 1600 + 400 =2000 miles

Hence, the distance covered by each train travel in total to reach its destination is 2000 miles.

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