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A manufacturer of calculators buys integrated circuits from supplies A,B and C. Fifty percents of the circuits come from A, 30% from B and 20% from C. One percent of the circuits supplied by A have been defective, 3% of Bs have been defective and 4% of C has been defective in the past.

(a) Suppose that a circuit is randomly selected. What is the probability that it is defective
(b) A circuit is selected at random and found to be defective. What is the probability it was manufactured by A?

Respuesta :

Answer:

0.022 and 0.2273

Step-by-step explanation:

Given that a manufacturer of calculators buys integrated circuits from supplies A,B and C.

Supplies A B C Total

   

Circuits 0.5 0.3 0.2 1

Defective 0.01 0.03 0.04  

   

P(defective)  0.5*0.01+0.3*0.03+0.2*0.04  

 0.022  

So probability for defective = 0.022

b) Prob ( circuit selected is from A/circuit defective)

= [tex]\frac{0.5*0.01}{0.022} \\=0.2273[/tex]

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