Answer: 4) y = -1/3x² + 2x - 1
Step-by-step explanation:
Given :
y = [tex]\frac{-1}{3}[/tex][tex](x-3)^{2}[/tex] + 2
Expanding (x-3)² will give :
[tex]x^{2}[/tex] - 6x + 9
substituting into the function , we have :
y = [tex]\frac{-1}{3}[/tex][tex] ( [tex]x^{2}[/tex] - 6x + 9 ) + 2
Expanding , we have
y = [tex]\frac{-1}{3}[/tex][tex]x^{2}[/tex] + 2x - 3 + 2
y = [tex]\frac{-1}{3}[/tex][tex]x^{2}[/tex] + 2x - 1