bdog5
contestada

A circle has a diameter
with endpoints at (10, 8)
and (5, 4). What is the
circumference of this
circle?​

Respuesta :

The circumference of circle is 20.096 units

Solution:

Given that circle has a diameter  with endpoints at (10, 8)  and (5, 4)

To get the diameter, find the distance between the end points

The distance between two points is given by formula;

[tex]d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}[/tex]

Here the points are (10, 8)  and (5, 4)

[tex](x_1, y_1) = (10, 8)\\\\(x_2, y_2) = (5, 4)[/tex]

Substituting the values we get,

[tex]\begin{aligned}&d=\sqrt{(5-10)^{2}+(4-8)^{2}}\\\\&d=\sqrt{(-5)^{2}+(-4)^{2}}=\sqrt{25+16}=\sqrt{41}\end{aligned}[/tex]

[tex]d = \sqrt{41} = 6.4[/tex]

Thus the diameter is 6.4 units

The  circumference of the circle is given by formula:

[tex]c = \pi d[/tex]

Where "d" is the diameter of circle

[tex]c = 3.14 \times 6.4 = 20.096[/tex]

Thus circumference of circle is 20.096 units