Answer:primary current is 3A
Explanation:
primary voltage Vp=240V
secondary voltage Vs=60V
resistance 5Ω
primary current in the circuit is
[tex]I_{P} =I_{S} \frac{V_{S}}{V_{P}}\\I_{P} =\frac{V_{S}}{R} \frac{V_{S}}{V_{P}}\\I_{P}=\frac{60\times 60}{5\times 240\\}\\I_{P}=3 A[/tex]
